Questions: Properties of Abelian Categories

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A mathematician wants to prove the snake lemma for the category of sheaves of abelian groups on a topological space. She reasons: 'I'll do an element chase, but sheaves don't have elements in the usual sense — is this valid?' Which theorem directly licenses this approach?

AThe Yoneda lemma — every category embeds fully into its presheaf category, where morphisms become natural transformations that can be checked pointwise
BThe Freyd-Mitchell embedding theorem — every small abelian category embeds fully and faithfully into a category of R-modules for some ring R, so element-level diagram chases transfer back automatically
CThe adjoint functor theorem — because the forgetful functor from sheaves to sets has a left adjoint, element arguments can be transported across the adjunction
DThe universal coefficient theorem — which converts homological results from module categories to arbitrary abelian categories
Question 2 Multiple Choice

A short exact sequence 0 → A → B → C → 0 of abelian groups does not split (B is not isomorphic to A ⊕ C). Which algebraic object classifies all non-isomorphic extensions of C by A?

AHom(C, A) — the abelian group of all homomorphisms from C to A
BExt¹(C, A) — the first derived functor of Hom, which vanishes if and only if every extension of C by A splits
CTor₁(C, A) — which measures the failure of the tensor product to be exact
DEnd(B) — the endomorphism ring of the middle object B in the sequence
Question 3 True / False

In an abelian category, the canonical map from the coimage of f (the cokernel of ker f) to the image of f (the kernel of coker f) is always an isomorphism — this is the categorical form of the first isomorphism theorem.

TTrue
FFalse
Question 4 True / False

The Freyd-Mitchell embedding theorem implies that nearly every abelian category is actually a full category of modules over some ring, making the abstract categorical language redundant for most homological algebra.

TTrue
FFalse
Question 5 Short Answer

Why does the Freyd-Mitchell embedding theorem matter for mathematicians working in abelian categories like sheaves of abelian groups, which have no 'elements' in the usual sense?

Think about your answer, then reveal below.