Questions: Acoustic Resonance in Strings and Tension
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
A guitar string of length L resonates at fundamental frequency f₁. A guitarist frets the string at the midpoint, halving the vibrating length while keeping tension and mass density unchanged. The new fundamental frequency is...
A2f₁ — halving the length doubles the fundamental frequency
Bf₁/2 — a shorter string vibrates more slowly
C4f₁ — frequency scales as 1/L²
Df₁√2 — frequency scales as 1/√L
The fundamental frequency is f₁ = (1/2L)√(T/μ). Halving L gives f = (1/(2·L/2))√(T/μ) = (1/L)√(T/μ) = 2f₁. Frequency is inversely proportional to length (not length squared or √L), so halving the length doubles the frequency — exactly one octave higher. This is the physical basis for how fretting works on stringed instruments.
Question 2 Multiple Choice
Why are the resonant frequencies of a fixed string spaced at integer multiples of the fundamental (f₁, 2f₁, 3f₁, ...)?
ABecause each harmonic requires an integer number of half-wavelengths to fit between the fixed endpoints, and frequency is inversely proportional to wavelength at fixed wave speed
BBecause string tension increases proportionally with each successive harmonic, raising the frequency by equal steps
CBecause higher harmonics travel faster through the string, raising their frequency above the fundamental
DBecause each harmonic corresponds to a different linear mass density along the string
Fixed endpoints must be nodes, so the string length L must equal n·(λ/2) for integer n. This gives λₙ = 2L/n. Since f = v/λ, the resonant frequencies are fₙ = nv/(2L) = nf₁. The harmonic spacing is a direct consequence of the boundary constraint and the fixed wave speed — not changes in tension or density, which are properties of the string, not of the mode number.
Question 3 True / False
Increasing the tension of a guitar string raises all of its resonant frequencies — fundamental and harmonics alike.
TTrue
FFalse
Answer: True
True. The wave speed on the string is v = √(T/μ), so increasing tension T increases v. Since all resonant frequencies are fₙ = nv/(2L), every harmonic scales proportionally with v — the entire harmonic series shifts upward. A guitarist tightening a tuning peg raises the fundamental and all overtones simultaneously, maintaining the integer-multiple harmonic structure while shifting the overall pitch.
Question 4 True / False
The second harmonic of a string has twice the wavelength of the fundamental.
TTrue
FFalse
Answer: False
False — it has half the wavelength. The fundamental (n=1) has wavelength λ₁ = 2L: one half-wavelength fits across the string. The second harmonic (n=2) has two half-wavelengths fitting across L, so λ₂ = L = λ₁/2. The second harmonic has half the wavelength and twice the frequency of the fundamental. A common confusion is to associate 'second harmonic' with 'twice as large' — but wavelength and frequency move in opposite directions.
Question 5 Short Answer
Explain why a string fixed at both ends cannot resonate at an arbitrary driving frequency — why only certain discrete frequencies produce standing waves.
Think about your answer, then reveal below.
Model answer: A string fixed at both ends must have displacement nodes (zero motion) at both endpoints, since neither end can move. A stable standing wave requires the reflected waves from each end to arrive back in phase with the original wave. This happens only when the round-trip distance (2L) equals an integer multiple of the wavelength — equivalently, when an integer number of half-wavelengths fits exactly between the endpoints: L = nλ/2. At any other driving frequency, reflections arrive out of phase and destructively interfere, preventing any sustained standing wave from building up.
These discrete, allowed wavelengths λₙ = 2L/n directly determine the resonant frequencies fₙ = nv/(2L). The harmonic series is not a coincidence — it is the set of frequencies whose wavelengths are compatible with the boundary conditions. This same logic applies to any resonating system with two boundaries: open or closed organ pipes, quantum mechanical particle-in-a-box, microwave cavities.