Questions: Amine Reactivity: Nucleophilicity and Basicity

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Diisopropylamine (conjugate acid pKₐ ≈ 11) reacts far more slowly with methyl iodide than methylamine (conjugate acid pKₐ ≈ 10.6), despite being a slightly stronger base. What best explains this?

AThe electron-withdrawing isopropyl groups reduce the electron density on nitrogen, making it less nucleophilic
BThe bulky isopropyl groups sterically shield the nitrogen lone pair, reducing its nucleophilicity toward carbon electrophiles even though basicity (proton affinity) remains high
CMethylamine is a stronger nucleophile precisely because it is a weaker base — basicity and nucleophilicity always trade off
DThe reaction with methyl iodide proceeds through a proton-transfer mechanism, which favors weaker bases
Question 2 Multiple Choice

Aniline (PhNH₂, conjugate acid pKₐ ≈ 4.6) is a far weaker base than cyclohexylamine (conjugate acid pKₐ ≈ 10.7) primarily because:

AThe aromatic ring withdraws electrons inductively through σ bonds, reducing nitrogen's electron density
BNitrogen in aniline is sp² hybridized and geometrically unable to accept a proton
CThe nitrogen lone pair in aniline is delocalized into the π system of the aromatic ring, making it less available for protonation
DAniline's conjugate acid (anilinium) is destabilized by electrostatic repulsion from the aromatic ring
Question 3 True / False

A bulky amine like diisopropylamine can be a stronger base than a smaller amine while simultaneously being a weaker nucleophile toward carbon electrophiles, because steric effects impact reaction kinetics more than they impact equilibrium proton affinity.

TTrue
FFalse
Question 4 True / False

Because basicity and nucleophilicity both depend on the nitrogen lone pair, a stronger amine base will typically be a better nucleophile toward carbon electrophiles.

TTrue
FFalse
Question 5 Short Answer

A chemist wants to deprotonate the α-carbon of a ketone to form an enolate without any addition to the carbonyl group. Why would they choose LDA (lithium diisopropylamide) rather than a small primary amine like n-propylamine?

Think about your answer, then reveal below.