Explain why atmospheric pressure decreases faster near sea level than at high altitude, even though the pressure-altitude relationship is described as exponential.
Think about your answer, then reveal below.
Model answer: Near sea level, air density is high, so a thin layer of air has a large weight per unit area, causing pressure to drop steeply with even a small gain in altitude. At high altitude, the air is already thin (low density), so each additional kilometer of atmosphere contributes less weight. The hydrostatic equation (dP/dz = −ρg) shows that the pressure gradient is proportional to density — and density itself decreases with altitude — producing the characteristic exponential decay where the rate of decrease is always proportional to the current pressure.
This tests whether students understand that exponential decay means the rate of change is proportional to the current value. The misconception is to picture pressure decreasing at a constant rate. In reality, the hydrostatic equation and ideal gas law together yield P(z) = P₀·exp(−z/H) where H ≈ 8.5 km is the scale height, so each scale-height gain in altitude reduces pressure by the same factor (≈1/e), not by the same absolute amount.