Questions: Axiom Schema of Separation

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Why doesn't the formula {x ∈ A : x ∉ x} generate Russell's paradox in ZFC?

ABecause 'x ∉ x' is not a valid first-order formula in ZFC's language
BBecause the axiom of regularity separately guarantees no set contains itself
CBecause you must specify an existing set A, and ZFC never asserts that a universal set exists to use as A
DBecause the axiom of separation only applies to sets with finitely many elements
Question 2 Multiple Choice

Which of the following correctly uses the axiom of separation to construct the intersection A ∩ B?

A{x : x ∈ A and x ∈ B} — form the collection of all things satisfying both conditions
B{x ∈ A : x ∈ B} — carve from the existing set A exactly those elements also in B
C{x ∈ A ∪ B : x ∈ A and x ∈ B} — begin from the union and filter down
D{x ∈ A ∩ B : x ∈ A} — start from the intersection to define the intersection
Question 3 True / False

The axiom schema of separation is technically an infinite collection of axioms — one instance for each first-order formula φ — because first-order logic cannot quantify over formulas directly.

TTrue
FFalse
Question 4 True / False

The axiom of separation allows you to form the set {x : x = x} — the set of most self-identical things — because x = x is a valid first-order formula.

TTrue
FFalse
Question 5 Short Answer

Explain why the restriction 'x ∈ A' in {x ∈ A : φ(x)} is the fundamental fix for Russell's paradox, not merely a technical refinement.

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