Questions: Bijections and Cardinality Equivalence

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Which function establishes that the set of even natural numbers E = {0, 2, 4, 6, ...} has the same cardinality as the natural numbers ℕ = {0, 1, 2, 3, ...}?

Af(n) = n + 2, which shifts each natural number up by 2
Bf(n) = 2n, which maps every natural number to a distinct even number and covers all of E
CNo such function can exist because E is a proper subset of ℕ and must therefore be smaller
Df(n) = n², because squares grow fast enough to reach all even numbers
Question 2 Multiple Choice

A student argues that the integers ℤ must have larger cardinality than the natural numbers ℕ, because ℤ contains all of ℕ plus all negative integers. What is wrong with this reasoning?

ANothing — ℤ does have strictly larger cardinality than ℕ by Cantor's theorem
BThe student is confusing subset containment with cardinality; a bijection from ℕ to ℤ can be constructed, showing they are equinumerous
CThe reasoning is correct for finite sets but the conclusion happens to be wrong for infinite sets for unrelated reasons
Dℤ is actually smaller than ℕ because the negative integers cancel out the positive ones
Question 3 True / False

If set A is a proper subset of set B (meaning A ⊂ B and A ≠ B), then A typically has strictly smaller cardinality than B.

TTrue
FFalse
Question 4 True / False

A bijection between two sets A and B is a function that is both injective (one-to-one) and surjective (onto).

TTrue
FFalse
Question 5 Short Answer

Why is the existence of a bijection the right definition of 'same cardinality,' and what makes this definition more powerful than simply counting elements when dealing with infinite sets?

Think about your answer, then reveal below.