5 questions to test your understanding
A system's open-loop Bode phase plot shows −165° at the gain crossover frequency (where the magnitude equals 0 dB). What is the phase margin?
Adding a zero (a factor of the form (1 + s/ω₀)) to a transfer function changes the high-frequency Bode magnitude slope by:
Using a logarithmic frequency axis on a Bode plot transforms products of transfer function factors into sums, enabling graphical construction by adding individual factor contributions.
The bandwidth of a system can be read from a Bode plot as the frequency where the phase response crosses −90°.
Why does expressing gain in dB on a logarithmic frequency scale make Bode plot construction practical, when a linear-scale plot of the same system would be unreadable?