Questions: Bode Plot Construction and Interpretation

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A system's open-loop Bode phase plot shows −165° at the gain crossover frequency (where the magnitude equals 0 dB). What is the phase margin?

A−165°
B165°
C15°
D−15°
Question 2 Multiple Choice

Adding a zero (a factor of the form (1 + s/ω₀)) to a transfer function changes the high-frequency Bode magnitude slope by:

A−20 dB/decade — zeros attenuate high-frequency signals
B+20 dB/decade — zeros add a positive slope contribution above the corner frequency
C−40 dB/decade — a zero introduces a two-decade rolloff
D0 dB/decade — zeros only affect phase, not magnitude
Question 3 True / False

Using a logarithmic frequency axis on a Bode plot transforms products of transfer function factors into sums, enabling graphical construction by adding individual factor contributions.

TTrue
FFalse
Question 4 True / False

The bandwidth of a system can be read from a Bode plot as the frequency where the phase response crosses −90°.

TTrue
FFalse
Question 5 Short Answer

Why does expressing gain in dB on a logarithmic frequency scale make Bode plot construction practical, when a linear-scale plot of the same system would be unreadable?

Think about your answer, then reveal below.