A function f(z) = u(x,y) + iv(x,y) has continuous partial derivatives at z₀ and satisfies ∂u/∂x = ∂v/∂y and ∂u/∂y = −∂v/∂x there. Which conclusion follows?
Af is real-differentiable at z₀ as a map from ℝ² to ℝ², but not necessarily complex-differentiable
Bf is holomorphic (complex-differentiable) at z₀
Cu and v are each harmonic on all of ℂ
Df can be extended to a real-analytic function on a neighborhood of z₀
The Cauchy-Riemann equations together with continuity of partial derivatives are necessary and sufficient for complex differentiability at a point. Option A is wrong: satisfying the CR equations with continuous partials implies complex differentiability, which is stronger than (and implies) real differentiability, not the other way around. Option C overstates scope — harmonicity holds locally at the point, not necessarily on all of ℂ.
Question 2 Multiple Choice
What is the geometric meaning of the Cauchy-Riemann equations, distinguishing holomorphic maps from arbitrary real-differentiable maps?
AThey force u and v to be polynomials, restricting holomorphic functions to algebraic expressions
BThey require f to map circles to circles, ruling out functions with varying scale
CThey restrict the local linear approximation to rotation and uniform scaling, ruling out shear or differential stretching
DThey require the Jacobian matrix of f to have positive determinant, ensuring orientation preservation
A real-differentiable map from ℝ² to ℝ² can have any 2×2 Jacobian. The CR equations restrict the Jacobian to matrices of the form [[a, −b],[b, a]], corresponding precisely to multiplication by the complex number a + ib — a rotation and uniform scaling. This eliminates shear, differential stretching, and orientation-reversing maps. Option D is weaker: positive determinant only ensures orientation preservation, whereas CR equations impose the much stronger condition of conformality.
Question 3 True / False
If f(z) = u(x,y) + iv(x,y) is holomorphic on a simply connected domain, the harmonic conjugate of u is determined uniquely.
TTrue
FFalse
Answer: False
Given a harmonic function u on a simply connected domain, the CR equations can be integrated to find v such that f = u + iv is holomorphic. But v is determined only up to an additive real constant: if v₀ is one harmonic conjugate, then v₀ + c for any real constant c also satisfies the CR equations with u. This mirrors how antiderivatives in single-variable calculus are defined only up to a constant.
Question 4 True / False
Complex differentiability is strictly stronger than real differentiability: there exist functions that are real-differentiable everywhere but nowhere holomorphic.
TTrue
FFalse
Answer: True
A real-differentiable function f: ℝ² → ℝ² only requires the linear approximation to exist; it can have any 2×2 Jacobian. Complex differentiability additionally requires that Jacobian to satisfy the CR equations. The function f(z) = z̄ (complex conjugate) is real-differentiable everywhere — its Jacobian is the constant matrix [[1, 0],[0, −1]] — but nowhere holomorphic because it reverses orientation and violates the CR equations (∂u/∂x = 1 but ∂v/∂y = −1).
Question 5 Short Answer
Derive the Cauchy-Riemann equations from the definition of complex differentiability by computing the limit of [f(z₀+Δz)−f(z₀)]/Δz along two different paths.
Think about your answer, then reveal below.
Model answer: Write f(z) = u(x,y) + iv(x,y). Along the real axis (Δz = Δx): the limit is ∂u/∂x + i∂v/∂x. Along the imaginary axis (Δz = iΔy): the limit is (1/i)∂u/∂y + ∂v/∂y = ∂v/∂y − i∂u/∂y. Setting the two limits equal — real parts equal and imaginary parts equal — gives ∂u/∂x = ∂v/∂y and ∂u/∂y = −∂v/∂x.
The derivation reveals why complex differentiability is so restrictive: the limit must be path-independent. Even requiring agreement along just two axis directions forces a coupling between all four partial derivatives. When partial derivatives are also continuous, this two-direction agreement is enough to guarantee the limit is the same from every direction — a non-trivial fact that makes holomorphic functions far more special than real-differentiable ones.