Questions: Cavity Resonators and Standing Wave Patterns

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A rectangular cavity resonator has dimensions a × b × d. All three dimensions are doubled to 2a × 2b × 2d. How do the resonant frequencies change?

AAll resonant frequencies double, because the cavity is larger
BAll resonant frequencies are halved, because larger dimensions allow longer wavelengths
COnly the lowest resonant frequency changes; higher modes are unaffected
DResonant frequencies change unpredictably, depending on which mode is excited
Question 2 Multiple Choice

Why does a metal cavity resonator typically have a much higher quality factor Q than a simple resistive LC circuit?

ABecause the cavity stores no energy between driving cycles, reducing dissipation
BBecause energy losses occur only in the thin skin-depth layer at the conducting walls, while the bulk of stored energy resides in the fields inside the cavity
CBecause the resonant frequency is fixed by geometry, eliminating thermal noise
DBecause standing waves in a cavity reflect energy rather than dissipating it
Question 3 True / False

In a cavity resonator, energy alternates between electric and magnetic field storage — analogous to a mass-spring oscillator exchanging potential and kinetic energy.

TTrue
FFalse
Question 4 True / False

A cavity resonator supports a continuous range of resonant frequencies, like a transmission line, but reflects power back at both ends instead of transmitting it.

TTrue
FFalse
Question 5 Short Answer

Why does enclosing a waveguide at both ends with conducting walls produce discrete resonant modes rather than a continuous range of propagating frequencies?

Think about your answer, then reveal below.