Questions: Character Tables and Spectroscopic Selection Rules

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A vibrational mode in a C₂ᵥ molecule belongs to the B₁ irrep, which appears alongside the function x in the character table. What can you conclude about this mode?

AIt is IR-active because B₁ is a non-totally-symmetric irrep
BIt is IR-active because x is a translational (dipole) component, and IR activity requires matching a dipole irrep
CIt is Raman-active only, because B₁ does not equal A₁
DIts spectroscopic activity cannot be determined from the character table alone
Question 2 Multiple Choice

A student argues that a vibrational mode is IR-active whenever its irrep is the totally symmetric representation A₁. This reasoning is:

ACorrect — all A₁ modes are IR-active in every point group
BCorrect — the direct product of any irrep with A₁ always contains A₁
CIncorrect — IR activity requires the mode to share an irrep with x, y, or z (the dipole components), which may not be A₁
DIncorrect — A₁ modes are Raman-active by definition, not IR-active
Question 3 True / False

In a molecule with an inversion center (such as CO₂ or benzene), no single vibrational mode can be both IR-active and Raman-active.

TTrue
FFalse
Question 4 True / False

The characters in a character table represent the energy eigenvalues of molecular orbitals under each symmetry operation.

TTrue
FFalse
Question 5 Short Answer

Why do chemists need to know the irreducible representation (irrep) of a vibrational mode, rather than just its frequency, to predict whether it will appear in an IR spectrum?

Think about your answer, then reveal below.