Questions: Bacterial Chemotaxis and Two-Component Signal Transduction

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

An E. coli bacterium swims into a region with uniformly very high attractant concentration and remains there. After the adaptation mechanism has fully reset, what happens to the bacterium's tumbling frequency?

ATumbling frequency remains permanently suppressed because the high attractant concentration continuously inhibits CheA
BTumbling frequency returns to its pre-stimulus baseline, because methylation has restored CheA activity despite the high attractant
CTumbling frequency increases above baseline because high attractant saturates the receptors and disrupts normal signaling
DTumbling frequency stays low only if the bacterium continues to move — once it stops, adaptation occurs
Question 2 Multiple Choice

In the E. coli chemotaxis system, what is the direct effect of phosphorylated CheY (CheY-P) on flagellar rotation?

ACheY-P binds the flagellar motor switch complex and promotes counterclockwise rotation, extending runs
BCheY-P inhibits CheA autophosphorylation, creating a negative feedback loop that prevents over-tumbling
CCheY-P diffuses to the flagellar motor, binds the switch complex, and promotes clockwise rotation, causing tumbling
DCheY-P activates CheR to add methyl groups to the MCPs, resetting receptor sensitivity
Question 3 True / False

Bacteria navigate chemical gradients by sensing the rate of change (gradient) in attractant concentration rather than its absolute value.

TTrue
FFalse
Question 4 True / False

Attractant binding to chemoreceptors directly activates CheA, which then phosphorylates CheY to promote running behavior.

TTrue
FFalse
Question 5 Short Answer

How does the methylation-based adaptation mechanism allow bacteria to detect chemical gradients over a concentration range spanning five orders of magnitude?

Think about your answer, then reveal below.