Questions: The Chinese Remainder Theorem and Its Applications

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

You want to solve the system x ≡ 3 (mod 4) and x ≡ 1 (mod 6). Can the Chinese Remainder Theorem be directly applied?

AYes — there are two congruences and two unknowns, so CRT applies
BNo — 4 and 6 share a common factor of 2, so the moduli are not pairwise coprime and CRT's uniqueness guarantee fails
CYes — CRT applies to any system of linear congruences regardless of the moduli
DNo — CRT only works when all moduli are prime numbers
Question 2 Multiple Choice

Why does CRT require moduli to be pairwise coprime? What goes wrong if two moduli share a common factor?

AShared factors make the arithmetic harder to compute, but solutions still always exist
BShared factors mean the total modulus N = n₁n₂⋯nₖ would be too large for practical computation
CShared factors create dependencies between remainders — not every combination is achievable, so the bijection between remainder tuples and residues mod N breaks down
DShared factors only matter when the moduli are larger than 100
Question 3 True / False

For pairwise coprime moduli n₁, n₂, …, nₖ with N = n₁n₂⋯nₖ, every tuple of remainders (a₁, a₂, …, aₖ) corresponds to exactly one value of x in the range [0, N).

TTrue
FFalse
Question 4 True / False

If x₀ is a solution to a CRT system with moduli n₁, n₂, …, nₖ and N = n₁n₂⋯nₖ, then x₀ + N is also a valid solution.

TTrue
FFalse
Question 5 Short Answer

Explain why the pairwise coprimality requirement is essential to CRT. What goes wrong if two moduli share a common factor?

Think about your answer, then reveal below.