Questions: Closed Categories and Internal Hom-objects

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

In a closed monoidal category, the tensor-hom adjunction states that for all objects A, B, C there is a natural bijection between morphisms. Which pair of hom-sets are in bijection?

AHom(A, B ⊗ C) ≅ Hom(A ⊗ B, C)
BHom(A ⊗ C, B) ≅ Hom(C, [A, B])
CHom(A, [B, C]) ≅ Hom(A ⊗ B, A ⊗ C)
DHom([A, B], C) ≅ Hom(A, B ⊗ C)
Question 2 Multiple Choice

A student argues: 'In the category of sets, the internal hom [A, B] is just the set B^A of functions from A to B, so it is the same as the external hom-set Hom(A, B). Therefore internalizing the hom-functor adds nothing new in Set.' What is wrong with this argument?

AThe argument is correct — internal and external homs coincide in Set and the distinction only matters in non-concrete categories
BThe sets B^A and Hom(A, B) are different objects; internal homs always have additional algebraic structure not present in hom-sets
CWhile they happen to coincide in Set, the value of internal homs is that they live inside the category as objects that can be further composed and mapped — unlike external hom-sets which land in Set regardless of the ambient category
DThe argument fails because Hom(A, B) in Set is not a set but a proper class
Question 3 True / False

In any cartesian closed category, the categorical operation of currying is an instance of the tensor-hom adjunction where the monoidal product is the Cartesian product.

TTrue
FFalse
Question 4 True / False

Nearly every monoidal category is automatically closed, because the monoidal product ⊗ generally has a right adjoint given by the opposite monoidal structure.

TTrue
FFalse
Question 5 Short Answer

Why does it matter that internal hom-objects [A, B] live inside the category, rather than always living in Set as external hom-sets do? Give a concrete consequence of this internalization.

Think about your answer, then reveal below.