Questions: Complex Impedance in AC Networks

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A capacitor has impedance Z_C = 1/(jωC). As frequency increases from 100 Hz to 10,000 Hz, what happens to the capacitor's impedance magnitude, and what does this mean for current flow?

AImpedance increases — the capacitor becomes harder to drive at higher frequencies, limiting current
BImpedance decreases — the capacitor passes high-frequency signals more easily, as |Z_C| = 1/(ωC) shrinks with increasing ω
CImpedance stays constant — frequency does not affect the capacitor's opposition to current
DImpedance becomes purely resistive at high frequencies as the imaginary part cancels
Question 2 Multiple Choice

A series RC circuit has R = 3 Ω and capacitive reactance X_C = −4 Ω. What are the impedance magnitude and the phase angle between voltage and current?

A|Z| = 7 Ω, phase angle = −53° (current leads voltage by 53°)
B|Z| = 5 Ω, phase angle = −53° (current leads voltage by 53°)
C|Z| = 5 Ω, phase angle = +53° (voltage leads current by 53°)
D|Z| = 1 Ω, phase angle = −53° (current leads voltage by 53°)
Question 3 True / False

In AC circuit analysis, working with admittance Y = 1/Z is useful for parallel combinations because parallel admittances add, just as parallel conductances add in DC circuits.

TTrue
FFalse
Question 4 True / False

An inductor and a capacitor in series usually have zero total impedance because their reactances have opposite signs and cancel substantially.

TTrue
FFalse
Question 5 Short Answer

A DC-trained engineer says 'For AC circuits, I just replace every R with Z and use all the same DC formulas.' Explain why this works, and what the complex nature of Z adds that DC analysis cannot capture.

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