Questions: Compressibility Factor and Reduced Properties

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

At moderate temperature and elevated pressure, nitrogen gas is measured to have Z = 0.87. What does this tell you about nitrogen's behavior compared to an ideal gas at the same conditions?

ANitrogen occupies more volume than an ideal gas — repulsive forces dominate
BNitrogen behaves almost ideally because Z is close to 1, so the ideal gas law is accurate
CNitrogen occupies less volume than an ideal gas — intermolecular attractive forces draw molecules closer than ideal behavior predicts
DThe measurement indicates nitrogen is in a liquid phase at these conditions
Question 2 Multiple Choice

The law of corresponding states allows engineers to estimate compressibility factors for unfamiliar gases using a single generalized chart. What makes this possible?

AAll gases have the same molecular size and intermolecular forces at high temperatures
BThe ideal gas law applies to all gases equally, so corrections are universal
CWhen T and P are scaled by critical properties (Tr = T/Tc, Pr = P/Pc), the Z vs. Tr and Pr curves for most simple gases approximately collapse onto a single universal surface
DThe compressibility factor is defined to equal 1 for all gases, so no gas-specific data is needed
Question 3 True / False

At very low pressures, all real gases approach Z = 1 regardless of temperature, because molecules are too far apart for intermolecular interactions to matter.

TTrue
FFalse
Question 4 True / False

A gas with Z > 1 is more compressed than an ideal gas at the same temperature and pressure, indicating strong intermolecular attractive forces.

TTrue
FFalse
Question 5 Short Answer

Explain why reduced properties (Tr = T/Tc, Pr = P/Pc) allow different gases to be compared on the same compressibility chart, rather than needing separate charts for each gas.

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