A figure skater spinning with arms extended pulls her arms in close to her body, halving her moment of inertia. What happens to her angular velocity?
AIt halves
BIt stays the same
CIt doubles
DIt quadruples
Angular momentum L = Iω is conserved because no external torque acts on the skater. If I decreases by half and L is constant, ω must double: L = I₁ω₁ = I₂ω₂ → ω₂ = (I₁/I₂)ω₁ = 2ω₁. The skater spins faster, but her total angular momentum is unchanged.
Question 2 True / False
When a figure skater pulls in her arms and spins faster, her angular momentum has increased.
TTrue
FFalse
Answer: False
This is a common misconception. Angular momentum is conserved — it does not change. What changes is how that fixed angular momentum is distributed: a smaller moment of inertia (arms in) requires a larger angular velocity to maintain the same L = Iω. The skater spins faster, but her total angular momentum is unchanged.
Question 3 Short Answer
What condition must be satisfied for the total angular momentum of a system to be conserved?
Think about your answer, then reveal below.
Model answer: The net external torque on the system must be zero.
This follows from Newton's second law for rotation: dL/dt = τ_net. If net external torque is zero, dL/dt = 0, so L is constant. Internal torques (forces between parts of the system) always come in equal and opposite pairs and cannot change the total angular momentum — only external torques can.