Questions: Dielectric Constant and Relative Permittivity

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A parallel-plate capacitor holds charge Q and has capacitance C₀ in vacuum. A dielectric with κ = 4 is inserted while charge Q is held fixed. What happens to the capacitance and the electric field inside?

ACapacitance increases to 4C₀; field decreases to E₀/4
BCapacitance decreases to C₀/4; field increases to 4E₀
CCapacitance increases to 4C₀; field remains E₀
DBoth capacitance and field increase by factor κ
Question 2 Multiple Choice

The displacement field D is introduced in Maxwell's equations primarily because:

AIt is easier to measure directly than the electric field E
BIt allows Gauss's law to be written in terms of free charges only, absorbing bound charges from polarization into the material constant ε
CIt replaces ε₀ entirely in all electromagnetic equations
DIt describes the force on a test charge inside a dielectric
Question 3 True / False

Inserting a dielectric into a capacitor increases its capacitance because the dielectric's polarization partially cancels the internal electric field, allowing more charge to be stored at the same voltage.

TTrue
FFalse
Question 4 True / False

The dielectric constant κ represents the absolute permittivity of a material — a quantity with units of farads per meter.

TTrue
FFalse
Question 5 Short Answer

Why does water have a dielectric constant of approximately 80 while nonpolar materials like most plastics have κ ≈ 2–4? Explain in terms of molecular structure.

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