Questions: Doppler Effect: Complete Analysis for Moving Source and Observer

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A train (source) moves toward you at 30 m/s and sounds its horn at 400 Hz. You walk toward the train at 2 m/s. Using v = 340 m/s, what is the observed frequency?

Af' = 400 × (340 − 2)/(340 − 30) ≈ 437 Hz (observer away subtracts; source toward subtracts)
Bf' = 400 × (340 + 2)/(340 + 30) ≈ 369 Hz (student treats both motions as additive in the same direction)
Cf' = 400 × (340 + 2)/(340 − 30) ≈ 441 Hz (observer toward adds in numerator; source toward subtracts in denominator)
Df' = 400 × (340)/(340 − 30) ≈ 439 Hz (only source motion enters the formula)
Question 2 Multiple Choice

A source moves toward you at speed vₛ. You move toward the source at the same speed vₛ. Are the contributions of these two motions to the observed frequency equal?

AYes — since both motions bring source and observer closer at the same rate, the Doppler shifts are equal and can be added symmetrically
BNo — source motion physically shortens the wavelength in the medium (denominator effect), while observer motion only increases the rate of wavefront encounters without changing the wavelength (numerator effect); they produce different frequency shifts even for equal speeds
CYes, but only when both speeds are much smaller than the wave speed v
DNo — observer motion has no effect on observed frequency; only source motion matters
Question 3 True / False

Source velocity appears in the Dopinator of the Doppler formula because a moving source physically changes the wavelength of waves in the medium.

TTrue
FFalse
Question 4 True / False

The classical Doppler formula f' = f(v ± vₒ)/(v ∓ vₛ) applies equally well to light (electromagnetic waves) from distant galaxies as to sound waves.

TTrue
FFalse
Question 5 Short Answer

Explain in physical terms why a moving source and a moving observer produce asymmetric contributions to the observed Doppler shift — specifically, why source velocity appears in the denominator and observer velocity in the numerator.

Think about your answer, then reveal below.