Questions: E2 Elimination Mechanism and Hoffmann's Rule

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

2-Bromobutane undergoes E2 elimination with potassium tert-butoxide (KOtBu). What is the major product, and why?

A2-Butene (more substituted), because Zaitsev's rule always predicts the thermodynamically stable product
B1-Butene (less substituted), because the bulky base cannot reach the more hindered internal β-hydrogen
C2-Butene (more substituted), because the anti-periplanar requirement favors the internal hydrogen
DA mixture of equal amounts of 1-butene and 2-butene, since base size doesn't affect regiochemistry
Question 2 Multiple Choice

The anti-periplanar requirement in E2 elimination means that...

AThe base must attack from the same face as the leaving group
BThe β-hydrogen and leaving group must be 180° apart when viewed along the breaking C–C bond
CThe reaction only proceeds when the substrate is a secondary alkyl halide
DThe reaction is reversible, allowing the molecule to adopt the required conformation
Question 3 True / False

Switching from sodium ethoxide (NaOEt) to potassium tert-butoxide (KOtBu) as the base for an E2 reaction can change the major alkene product without changing the substrate.

TTrue
FFalse
Question 4 True / False

Hoffmann's rule states that E2 eliminations generally produce the less substituted alkene as the major product.

TTrue
FFalse
Question 5 Short Answer

Explain why a bulky base like KOtBu produces the less substituted alkene in E2 elimination, even though the more substituted alkene is thermodynamically more stable.

Think about your answer, then reveal below.