Questions: Effective Field Theory

4 questions to test your understanding

Score: 0 / 4
Question 1 Multiple Choice

Fermi's theory of weak interactions describes beta decay using a four-fermion interaction G_F (psi-bar psi)(psi-bar psi), with Fermi constant G_F ~ 10^{-5} GeV^{-2}. This is an effective field theory. What is the 'UV completion' that Fermi's theory approximates?

AQED with virtual photon exchange
BThe electroweak theory with W boson exchange — at energies much below M_W ~ 80 GeV, the W propagator 1/(q^2 - M_W^2) reduces to -1/M_W^2, collapsing the exchange to a point-like four-fermion vertex with G_F ~ g^2/M_W^2
CQCD with gluon exchange
DString theory
Question 2 Multiple Choice

In EFT, higher-dimension operators are suppressed by powers of 1/Lambda (where Lambda is the high-energy scale). A dimension-6 operator is suppressed by 1/Lambda^2 relative to a dimension-4 operator. Why does this make EFT a systematic expansion?

ABecause Lambda is always infinite
BBecause at energies E << Lambda, the ratio (E/Lambda)^n decreases rapidly with n — dimension-6 operators contribute corrections of order (E/Lambda)^2, dimension-8 operators of order (E/Lambda)^4, and so on, giving a controlled perturbative expansion in powers of E/Lambda
CBecause higher-dimension operators are always zero
DBecause the EFT Lagrangian contains only finitely many operators
Question 3 True / False

The Standard Model itself is now widely regarded as an effective field theory valid up to some unknown scale Lambda. This is not a failure but a feature.

TTrue
FFalse
Question 4 Short Answer

Explain why non-renormalizable theories are not 'sick' but are perfectly well-defined effective field theories, and what changes about their predictive power compared to renormalizable theories.

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