Questions: Electron Diffraction and Matter Wave Properties
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
An electron is accelerated through a higher voltage in a diffraction experiment. Compared to a lower-voltage electron, how do its de Broglie wavelength and diffraction pattern change?
AHigher voltage → longer wavelength → more spread-out diffraction pattern
BHigher voltage → shorter wavelength → more tightly spaced diffraction fringes
CHigher voltage → shorter wavelength → wider diffraction pattern, because faster electrons scatter more
DVoltage does not affect wavelength; only the target crystal spacing determines the diffraction pattern
Higher voltage → greater kinetic energy → greater momentum p = √(2meV) → shorter de Broglie wavelength λ = h/p. Shorter wavelength produces diffraction maxima at smaller angles (from nλ = 2d sinθ, smaller λ means smaller θ), so the diffraction pattern is more compressed — fringes are more tightly spaced. The Common Misconceptions section notes that slower electrons have *longer* wavelengths and diffract *more*, which is the opposite of option A. Option D is wrong: crystal spacing d sets absolute angle positions, but changing λ predictably shifts the pattern.
Question 2 Multiple Choice
Why were nickel crystals — rather than a pair of narrow slits — the natural choice for demonstrating electron diffraction in the Davisson-Germer experiment?
ANickel is magnetic, which focuses the electron beam into a coherent stream before diffraction
BThe nickel crystal lattice spacing (~0.2 nm) is comparable to the de Broglie wavelength of electrons accelerated through tens of volts, making it an effective diffraction grating
CDouble slits can deflect electrons but cannot produce interference; only crystal planes create the necessary standing waves
DNickel produces fluorescence that makes diffraction patterns directly visible to the naked eye
For diffraction to produce observable interference, the aperture or grating spacing must be comparable to the wavelength. Electrons accelerated through 50–100 V have de Broglie wavelengths of ~0.1–0.2 nm — precisely the scale of atomic spacings in crystal lattices. Nickel's lattice spacing of ~0.2 nm acts as a natural diffraction grating at exactly the right scale. Double slits could also demonstrate electron diffraction, but achieving nanometer-scale slit separations was technically prohibitive in 1927. The crystal also provides a large, regular, well-characterized periodic structure.
Question 3 True / False
In a diffraction experiment, electrons accelerated through a lower voltage produce a more spread-out diffraction pattern than electrons at higher voltage.
TTrue
FFalse
Answer: True
Lower voltage → lower kinetic energy → lower momentum p = √(2meV) → longer de Broglie wavelength λ = h/p. From the Bragg condition nλ = 2d sinθ, a longer wavelength corresponds to a larger diffraction angle θ for each order n. The diffraction peaks appear at wider angles — a more spread-out pattern. This is a direct experimental handle on the de Broglie wavelength: adjusting the accelerating voltage predictably shifts the pattern in the direction the formula demands.
Question 4 True / False
In the Davisson-Germer experiment, electrons behaved as waves when reflecting from the crystal lattice but as particles when traveling through vacuum between the gun and the crystal.
TTrue
FFalse
Answer: False
This is precisely the misconception that complementarity corrects. Electrons do not switch between wave and particle behavior depending on where they are in the apparatus. They always possess both properties simultaneously. Whether wave-like behavior (interference, diffraction) or particle-like behavior (localized detection) is *manifest* depends entirely on the experimental arrangement — specifically, whether conditions permit interference to be observable. The periodic crystal provides those conditions; a which-path measurement would suppress the interference pattern and reveal particle-like localization instead.
Question 5 Short Answer
Why does measuring which crystal plane an electron reflected from destroy the diffraction pattern observed in the Davisson-Germer setup?
Think about your answer, then reveal below.
Model answer: Diffraction patterns arise from interference between electron waves reflecting from many parallel crystal planes simultaneously — the electron's wave function is spread across multiple planes, and contributions from different planes add constructively at specific angles. Measuring which specific plane an electron reflected from localizes the electron to a single plane, collapsing the spatial coherence between contributions from different planes. Without interference between waves from multiple planes, there are no diffraction maxima — only a diffuse, structureless reflection. The information gained (which-path knowledge) necessarily destroys the interference.
This is a fundamental instance of complementarity: wave and particle information cannot be simultaneously maximized. Any measurement that determines which path an electron took destroys the interference that depends on all paths being simultaneously active. It is not a technological limitation but a structural feature of quantum mechanics. Electron diffraction was the proof that matter waves are not a metaphor — and the which-path erasure is the proof that complementarity is not a metaphor either.