Questions: Elementary Submodels of ZFC

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A countable set M is constructed so that M ≺ V (the full set-theoretic universe). Inside M, the statement 'ℝ is uncountable' is true — M ⊨ ¬∃ bijection from ω to ℝ^M. From V's perspective, M itself is countable. How is this possible?

AIt is a contradiction — if M is countable then M cannot satisfy the uncountability of ℝ
BThe bijection between ω and M's reals exists in V but not in M, so uncountability is not absolute across models
CM uses a different logic where 'uncountable' means something weaker than in V
DThe Löwenheim-Skolem theorem guarantees that M is actually uncountable despite appearances
Question 2 Multiple Choice

What is the key difference between a formula being 'absolute' for a transitive model and a model being an 'elementary submodel'?

AThey are the same: absoluteness and elementarity both require all formulas to have the same truth value
BAbsoluteness applies only to Δ₀ (bounded) formulas; elementary submodels preserve all first-order formulas simultaneously
CElementary submodels are stronger because they must be transitive, while absolute formulas hold in non-transitive models
DAbsoluteness is a property of a single formula; elementary submodels only guarantee preservation of atomic formulas
Question 3 True / False

If M ≺ V, then M and V agree on which sets are countable — a set is countable in M if and only if it is countable in V.

TTrue
FFalse
Question 4 True / False

Every ZFC axiom holds in M if M ≺ V, because each ZFC axiom is a first-order sentence true in V.

TTrue
FFalse
Question 5 Short Answer

Explain why a countable elementary submodel M of V can satisfy 'there are uncountably many reals,' and what this reveals about the concept of uncountability in set theory.

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