Questions: Enols, Enolates, and the Aldol Reaction

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A chemist deprotonates the alpha carbon of acetone with a strong base to form an enolate. The enolate then attacks the carbonyl of benzaldehyde. Through which atom does the enolate carbon attack, and what new bond is formed?

AThe oxygen atom attacks; a new C–O bond forms, giving a vinyl ether product
BThe alpha carbon attacks; a new C–C bond forms, giving a beta-hydroxy carbonyl (aldol product)
CThe carbonyl carbon attacks; a new C–C bond forms at the wrong end of the enolate
DThe oxygen atom attacks; a new O–H bond forms, regenerating the enol
Question 2 Multiple Choice

A student draws keto and enol tautomers of acetaldehyde and labels them as 'resonance structures.' What is wrong with this?

ANothing — resonance and tautomerism are different names for the same phenomenon
BThe keto form has lower energy, so they cannot be in equilibrium
CThey are distinct chemical species with different atom connectivity, not different depictions of the same molecule
DAcetaldehyde does not have an enol form because it lacks an alpha carbon
Question 3 True / False

Keto-enol tautomers are resonance structures of a carbonyl compound.

TTrue
FFalse
Question 4 True / False

The reason alpha C–H bonds are unusually acidic (pKa ≈ 20) compared to typical C–H bonds (pKa ≈ 50) is that removal of the proton produces a carbanion stabilized by resonance delocalization onto the carbonyl oxygen.

TTrue
FFalse
Question 5 Short Answer

Why does the aldol reaction form a C–C bond at the alpha carbon specifically, rather than at the carbonyl carbon?

Think about your answer, then reveal below.