Questions: Evanescent Waves and Total Internal Reflection

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Two glass prisms are arranged hypotenuse-to-hypotenuse with an air gap. Total internal reflection occurs at the first hypotenuse. When the gap is reduced to a fraction of a wavelength, light is observed in the second prism. A student says: 'This is impossible — TIR means total reflection, so no field exists in the air gap.' What is the correct explanation?

AThe student is correct: reducing the gap mechanically disrupts the TIR condition, causing partial transmission through a different mechanism
BAt very small gaps, quantum tunneling allows photons to jump across the gap, bypassing the classical wave equations
CTIR reflects the traveling wave but an evanescent field — non-propagating, exponentially decaying — still exists in the air gap; when the second prism is close enough, this field couples into propagating modes there, transferring power (frustrated TIR)
DThe student is correct that no field exists, but diffraction at the edge of the prism redirects light into the second prism
Question 2 Multiple Choice

A wave vector k = iκ (with κ real and positive) in the wave factor e^{ikx} describes which physical situation?

AA traveling wave with a 90° phase shift relative to a standard plane wave
BA standing wave formed by two counterpropagating waves with equal amplitude
CAn exponentially decaying field (e^{−κx}) — an evanescent wave that carries no net power in the decay direction
DA wave with reduced phase velocity due to dispersion in a dense medium
Question 3 True / False

In total internal reflection, the electromagnetic field in the second (rarer) medium is exactly zero — TIR produces complete exclusion of the field from that medium.

TTrue
FFalse
Question 4 True / False

Because evanescent waves carry no net power, they have no physical consequences and can seldom be detected or exploited in technology.

TTrue
FFalse
Question 5 Short Answer

Why is frustrated total internal reflection considered the optical analogue of quantum-mechanical tunneling?

Think about your answer, then reveal below.