Questions: Feasible GLS (FGLS) with Estimated Covariance Structure

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A researcher has 40 observations with severe heteroskedasticity. She specifies an FGLS model assuming variance is proportional to x², estimates Ω̂ from OLS residuals, then applies GLS using Ω̂. But the true variance structure is actually proportional to x³. What is the most likely outcome?

AFGLS will still be efficient because any correction for heteroskedasticity improves on OLS
BFGLS may perform worse than both OLS and correct GLS due to misspecification of the covariance form
CFGLS will be unbiased but inefficient, with performance identical to OLS
DFGLS will be exactly as efficient as OLS because the sample size is too small for GLS improvements
Question 2 Multiple Choice

What does FGLS estimate in its first step, and why is this step necessary?

AThe regression coefficients β, which are then used to construct Ω̂
BThe error covariance structure Ω from OLS residuals, because true GLS requires knowing Ω a priori
CThe instrumental variables needed to address endogeneity in the transformed model
DThe optimal bandwidth for kernel-based heteroskedasticity correction
Question 3 True / False

In large samples, FGLS is asymptotically equivalent to true GLS — both achieve the same efficiency gains over OLS.

TTrue
FFalse
Question 4 True / False

FGLS is generally more efficient than OLS because it corrects for non-spherical errors, so it should be the default estimator whenever heteroskedasticity or autocorrelation is suspected.

TTrue
FFalse
Question 5 Short Answer

Why do practitioners often prefer heteroskedasticity-robust standard errors over FGLS when facing heteroskedasticity, even though FGLS explicitly models and corrects for the heteroskedasticity?

Think about your answer, then reveal below.