Questions: Ferromagnetism and Heisenberg Model

4 questions to test your understanding

Score: 0 / 4
Question 1 Multiple Choice

The exchange interaction J responsible for ferromagnetism has an electrostatic origin (Coulomb repulsion + Pauli exclusion), not a magnetic one. Why is this distinction important?

AIt means ferromagnetism is not really a magnetic phenomenon
BMagnetic dipole-dipole interactions between atomic moments give energies of order μ_B²/a³ ~ 0.1 K, far too small to explain Curie temperatures of ~1000 K. Exchange interactions are electrostatic (eV scale) and arise because the Pauli principle correlates spatial and spin wavefunctions — electrons with parallel spins must be spatially antisymmetric, reducing Coulomb repulsion
CIt means that ferromagnetism only occurs in metals
DThe exchange interaction is weaker than the dipole interaction but acts over longer range
Question 2 Multiple Choice

Mean-field theory predicts the critical exponent β = 1/2 for the spontaneous magnetization near T_C (M ∝ (T_C - T)^{1/2}). Experiment gives β ≈ 0.33 for real ferromagnets. What causes this discrepancy?

AMean-field theory neglects spin-orbit coupling
BMean-field theory replaces the actual fluctuating local environment with a single effective field, ignoring correlations and critical fluctuations near T_C. Near the critical point, fluctuations on all length scales become important, and the true critical behavior is determined by universality class (dimension and symmetry), not by mean-field theory
CThe Heisenberg model is fundamentally incorrect for real materials
DMean-field theory uses the wrong value of S for iron
Question 3 True / False

The Heisenberg model H = -J Σ S_i · S_j treats all spin components (S^x, S^y, S^z) symmetrically. The Ising model keeps only H = -J Σ S_i^z S_j^z. How does this symmetry difference affect the physics?

TTrue
FFalse
Question 4 Short Answer

Why are iron, cobalt, and nickel ferromagnetic while most other transition metals are not?

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