Questions: Generalized Coordinates and Degrees of Freedom

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A rigid bar connects two particles in 3D space. How many degrees of freedom does this two-particle system have?

A6 — three Cartesian coordinates for each particle
B5 — the rigidity constraint (fixed distance between particles) removes one degree of freedom
C4 — the bar removes two degrees of freedom because the particles cannot move independently
D3 — the rigid bar makes the pair equivalent to a single particle
Question 2 Multiple Choice

A coin rolls without slipping on a flat surface. The no-slip rolling condition is a non-holonomic constraint. What does this mean for the number of generalized coordinates needed to describe the coin's configuration?

AThe no-slip condition reduces the number of required generalized coordinates, just like a holonomic constraint would
BThe no-slip condition does not reduce the number of generalized coordinates — you still need as many parameters to specify the configuration fully
CThe no-slip condition eliminates all constraints on position, since it only affects velocity
DNon-holonomic constraints are ignored in Lagrangian mechanics and never affect generalized coordinate counts
Question 3 True / False

For a simple pendulum of length L, choosing the angle θ as the sole generalized coordinate automatically satisfies the length constraint without needing to impose it separately.

TTrue
FFalse
Question 4 True / False

For a system of N particles subject to k holonomic constraints, the degrees of freedom usually equals 3N − k, regardless of whether any non-holonomic constraints are also present.

TTrue
FFalse
Question 5 Short Answer

Explain what it means for generalized coordinates to 'build in' the constraints of a system, and why this makes the Lagrangian approach more efficient than applying Newtonian mechanics with explicit constraint forces.

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