Questions: Graph Minors and the Robertson–Seymour Theorem

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A researcher wants to know whether graphs embeddable on a torus (a donut-shaped surface) can be characterized by a finite list of forbidden minors. Before the Robertson–Seymour theorem, this was open. What does the theorem now guarantee?

AA finite forbidden minor characterization exists only for planar graphs; no such guarantee applies to other surfaces
BSince torus-embeddability is a minor-closed property, the Robertson–Seymour theorem guarantees a finite set of forbidden minors must exist, even though actually finding them may be extremely difficult
CThe theorem only applies to trees and tree-width bounded graphs; surface-embeddable graphs are out of scope
DMinor-closed properties require infinite forbidden minor sets; the theorem proves this is unavoidable
Question 2 Multiple Choice

What distinguishes obtaining a graph minor from obtaining a subdivision of a graph?

ASubdivisions can increase graph size; minors can only preserve or increase size through splitting
BMinors are restricted to planar graphs; subdivisions apply to all graphs regardless of planarity
CSubdivision inserts new vertices along edges (refining), while edge contraction in minor operations merges adjacent vertices — potentially reducing graph size
DThere is no meaningful difference — minor and subdivision are equivalent operations that produce the same set of graphs
Question 3 True / False

Before the Robertson–Seymour theorem, it was already well understood that nearly every minor-closed graph family should have a finite forbidden minor characterization.

TTrue
FFalse
Question 4 True / False

The well-quasi-ordering result implies that in any infinite sequence of graphs, at least one graph must be a minor of a later graph in the sequence — preventing the existence of infinitely many pairwise minor-incomparable graphs.

TTrue
FFalse
Question 5 Short Answer

Why is the Robertson–Seymour theorem considered a profound result rather than a straightforward generalization of Kuratowski's theorem?

Think about your answer, then reveal below.