5 questions to test your understanding
The graph of y = csc(x) has vertical asymptotes at which x-values?
A student claims y = tan(x) has amplitude 1 because it passes through (π/4, 1) and (−π/4, −1). What is wrong with this claim?
The graph of y = sec(x) and the graph of y = cos(x) touch (intersect) at every point where cos(x) = ±1.
The period of y = tan(x) is 2π, the same as the period of y = sin(x) and y = cos(x).
Explain why the zeros of y = sin(x) become vertical asymptotes on the graph of y = csc(x), using the relationship between a function and its reciprocal.