Questions: Hausman Test: Fixed Effects Versus Random Effects
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
You run a Hausman test comparing fixed effects (FE) and random effects (RE) estimators on panel data. The test statistic H is large with a very small p-value. What should you conclude and do?
AReject the null; both estimators are consistent but FE is more efficient, so use FE
BFail to reject the null; RE is preferred because it uses more variation and is more efficient
CReject the null; the RE orthogonality assumption likely fails, so use FE which remains consistent
DReject the null; neither estimator is reliable and you should use first-differences instead
A large H (small p-value) rejects the null hypothesis that the unobserved unit effects are uncorrelated with the regressors. Under the alternative, RE is biased and inconsistent (because it assumes orthogonality that doesn't hold), while FE remains consistent by differencing out the unit effects. You switch to FE. Option A has the efficiency claim backwards: it is RE that is more efficient under the null, not FE. Option D overstates the result — a Hausman rejection doesn't make FE unreliable, just RE.
Question 2 Multiple Choice
Under the null hypothesis of the Hausman test, why is random effects preferred over fixed effects despite both being consistent?
ARandom effects uses only within-unit variation, which is more reliable than cross-sectional variation
BRandom effects uses both within-unit and between-unit variation, producing estimates with smaller variance than fixed effects
CRandom effects is preferred because it does not require the strict exogeneity assumption that fixed effects does
DRandom effects has fewer parameters to estimate, making it computationally more tractable
Fixed effects eliminates unobserved heterogeneity by demeaning within each unit — but in doing so, it discards all cross-sectional (between-unit) variation. Random effects, when its orthogonality assumption holds, incorporates both within-unit and between-unit variation into a GLS-type estimator, using more information. More information translates to more efficient (lower variance) estimates. Efficiency is the precise statistical term for this advantage: under the null, RE is consistent AND uses more variation, so it is the better estimator.
Question 3 True / False
Rejecting the null hypothesis on the Hausman test means your fixed effects estimates are unbiased and fully reliable for causal inference.
TTrue
FFalse
Answer: False
A Hausman rejection tells you that RE is inconsistent — not that FE is perfect. FE is consistent under correlated unit effects, but it faces its own limitations: it cannot identify time-invariant variables (they are differenced out), it requires strict exogeneity of the regressors, and with short panels it can have finite-sample bias. A Hausman rejection is the beginning of careful analysis, not the end — it should prompt investigation of which variables drive the correlation between unit effects and regressors, since those omitted drivers may have substantive implications.
Question 4 True / False
Under the null hypothesis of the Hausman test, both the fixed effects and random effects estimators are consistent, but random effects is more efficient.
TTrue
FFalse
Answer: True
This is the core logic of the test. When the RE orthogonality assumption holds (unit effects uncorrelated with regressors), RE exploits both within-unit and between-unit variation — giving consistent estimates with smaller standard errors than FE, which only uses within variation. Under the alternative (correlated effects), RE becomes inconsistent while FE remains consistent. The test's power comes from comparing the two: if they agree (small H), RE's efficiency gain makes it the better choice; if they diverge (large H), only FE can be trusted.
Question 5 Short Answer
What is the key assumption of the random effects estimator that the Hausman test probes, and why does its violation render RE estimates inconsistent?
Think about your answer, then reveal below.
Model answer: The RE estimator assumes that the unobserved individual-specific effects (α_i) are uncorrelated with the regressors (X_it). If this orthogonality assumption fails — if, say, a person's unobserved ability is correlated with their observed education level — then the RE estimator attributes some of α_i's effect to the observed regressors, biasing the coefficient estimates. Because this bias does not vanish as the sample grows (the same mis-attribution persists for every unit), RE is inconsistent. FE avoids this by demeaning within each unit, which differences out α_i entirely and eliminates the source of bias.
The intuition parallels omitted variable bias: if an omitted variable (here, the unit effect) is correlated with an included regressor, its effect 'leaks' into that regressor's coefficient. RE's GLS structure implicitly controls for the unit effect only under the orthogonality assumption. When that fails, the control is incomplete. FE's within-transformation is exact — it removes the unit effect algebraically — at the cost of losing between-unit information. The Hausman test asks: is the information loss worth it? If the RE assumption fails, yes.