Questions: Heat Treatment of Steels

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

Why is as-quenched martensite so hard compared to slowly-cooled pearlite?

AMartensite is an FCC phase, which is inherently harder than the BCC ferrite in pearlite
BSupersaturated carbon trapped in the distorted body-centered tetragonal lattice blocks dislocation motion
CThe rapid quench introduces a very high dislocation density, and dislocation tangling is the primary strengthening mechanism
DMartensite contains more carbon by weight than austenite, and carbon itself is hard
Question 2 Multiple Choice

A steel part requires high surface hardness for wear resistance but enough toughness to resist fracture in service. Which heat treatment sequence best achieves this?

AAnneal at high temperature, then slow-cool to produce fully pearlitic microstructure
BQuench rapidly to form martensite, then temper at a moderate temperature to restore toughness
CQuench to martensite and leave it untempered — maximum hardness means maximum performance
DHeat to just below the eutectoid temperature and air-cool to produce bainite
Question 3 True / False

Tempering a quenched steel always reduces its hardness compared to the as-quenched state.

TTrue
FFalse
Question 4 True / False

Adding alloying elements such as chromium and manganese to steel makes it easier to form martensite because they push the TTT nose to the left, accelerating the austenite-to-pearlite transformation.

TTrue
FFalse
Question 5 Short Answer

Why is tempering necessary after quenching steel to martensite, and what happens at the atomic level during the tempering process?

Think about your answer, then reveal below.