Questions: Holomorphic Functions

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

The function f(z) = |z|² can be shown to be complex differentiable at z = 0. A student concludes it must therefore be holomorphic on a neighborhood of 0. What is wrong with this reasoning?

AThe function is not continuous at z = 0, so differentiability cannot be established there
BHolomorphic requires complex differentiability at every point in an open domain, not just at one isolated point — |z|² fails complex differentiability everywhere except z = 0
CReal-valued functions of a complex variable are never complex differentiable
DThe student is correct — differentiability at one point is sufficient to establish holomorphicity in a neighborhood
Question 2 Multiple Choice

In real analysis, a function can be differentiable exactly once — differentiable but not twice differentiable. What is the analogous situation for holomorphic functions?

AThe same situation occurs — a function can be complex differentiable exactly once on a domain
BThere is no such situation: complex differentiability on a domain automatically implies the function is infinitely differentiable
CComplex differentiability is weaker than real differentiability, so 'differentiable once but not twice' functions are more common
DOnly polynomial functions can be holomorphic, and polynomials are always infinitely differentiable
Question 3 True / False

A holomorphic function on a connected domain is completely determined by its values on any open subset of that domain.

TTrue
FFalse
Question 4 True / False

Nearly every differentiable function of a real variable, extended to the complex plane by ignoring the imaginary part — setting f(x + iy) = g(x) — is holomorphic.

TTrue
FFalse
Question 5 Short Answer

Why does complex differentiability impose far stronger constraints than real differentiability, and what is the key geometric reason?

Think about your answer, then reveal below.