Questions: Hydroboration-Oxidation: Anti-Markovnikov Addition

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A student argues that hydroboration-oxidation places the hydroxyl group on the less substituted carbon because a primary carbocation is more stable than a tertiary one. What is wrong with this reasoning?

APrimary carbocations are actually less stable than tertiary, so the argument is backwards
BNo carbocation intermediate forms — addition is concerted, and regiochemistry reflects steric preference of boron, not carbocation stability
CThe hydroxyl group actually ends up on the more substituted carbon in hydroboration-oxidation
DThe student is correct — carbocation stability does determine regiochemistry
Question 2 Multiple Choice

What is the stereochemical consequence of performing hydroboration-oxidation on (Z)-2-butene compared to (E)-2-butene?

ABoth give the same racemic product because the intermediate is planar
BBoth give the same product because stereochemistry is lost during the oxidation step
CThey give different stereoisomeric products because syn addition preserves the relative face of addition from the starting alkene geometry
DThey give enantiomers of each other because the reaction proceeds through a carbocation that can be attacked from either face
Question 3 True / False

Hydroboration-oxidation places the hydroxyl group on the less substituted carbon because boron forms a more stable primary carbocation at that position.

TTrue
FFalse
Question 4 True / False

The syn addition observed in hydroboration-oxidation means that boron and hydrogen add to the same face of the alkene double bond.

TTrue
FFalse
Question 5 Short Answer

Why does hydroboration-oxidation give anti-Markovnikov regiochemistry, and how does this differ mechanistically from reactions that follow Markovnikov's rule?

Think about your answer, then reveal below.