Evaluate cosh 0 and sinh 0, and explain why cosh x ≥ 1 for all real x.
Think about your answer, then reveal below.
Model answer: cosh 0 = 1 and sinh 0 = 0. Since cosh²x = 1 + sinh²x ≥ 1 and cosh x is positive, cosh x ≥ 1.
At x = 0, e⁰ = 1, so cosh 0 = (1 + 1)/2 = 1 and sinh 0 = (1 - 1)/2 = 0. The identity forces cosh²x ≥ 1, and cosh x is a sum of positive terms divided by 2, so cosh x ≥ 1.
Question 4 Multiple Choice
Which curve describes the shape of a flexible cable hanging under its own weight between two supports?
AA parabola y = ax²
BA catenary y = a cosh(x/a)
CA sine curve y = a sin(x)
DA circle
A uniform hanging cable forms a catenary, which is a scaled hyperbolic cosine. It resembles a parabola near its lowest point but is a different curve.