Questions: Induced Polarization and Frequency-Domain Response

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A geophysicist surveys a region looking for disseminated copper sulfide mineralization. Standard resistivity measurements show no anomaly, but an IP survey reveals a strong response. Why does IP succeed where resistivity fails?

AIP uses higher voltages that penetrate deeper, reaching ore bodies that resistivity cannot detect
BDisseminated sulfides have high polarizability from electrode polarization at grain boundaries, even though they are too sparse to significantly alter bulk resistivity
CSulfide minerals are always highly resistive, which IP measures more accurately than standard methods
DIP averages readings over wider areas, smoothing out the small resistivity signature of disseminated ore
Question 2 Multiple Choice

In time-domain IP, when is the chargeability signal measured?

AWhile the current pulse is actively flowing — measuring the enhanced conductivity of polarizable minerals
BSimultaneously at two frequencies — comparing resistivity at high and low frequency
CAfter the current is abruptly cut off — measuring the slowly decaying residual voltage
DBefore the current pulse — establishing a baseline that is subtracted from the active measurement
Question 3 True / False

In time-domain IP, the chargeability signal is measured from the decaying voltage that persists after the injected current is shut off.

TTrue
FFalse
Question 4 True / False

Electrode polarization in IP is caused by clay minerals partially blocking ion flow through narrow pore throats.

TTrue
FFalse
Question 5 Short Answer

Explain why IP measurements reveal properties of subsurface materials that standard resistivity measurements cannot detect.

Think about your answer, then reveal below.