Questions: IUPAC Nomenclature of Alkenes

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A molecule has a 8-carbon chain with no double bond and a separate 6-carbon chain that includes a C=C. Which chain must serve as the parent chain for IUPAC naming?

AThe 8-carbon chain, because IUPAC rules always select the longest continuous chain
BThe 6-carbon chain, because the parent chain must contain the double bond even if a longer all-single-bond chain exists
CEither chain may be selected, with the double bond named as a substituent on whichever chain is chosen
DThe 8-carbon chain, with the double bond assigned a separate locant as a branch
Question 2 Multiple Choice

Consider (Z)-1-chloro-2-fluoroethene. At C1: Cl (Z=17) and H (Z=1), so Cl has higher priority. At C2: F (Z=9) and H (Z=1), so F has higher priority. The higher-priority groups (Cl and F) are on the same side. A student concludes 'Z always means the same side, just like cis.' When does this reasoning break down?

AIt breaks down for terminal alkenes, which are always assigned Z regardless of substituent arrangement
BIt breaks down whenever there are three or four different substituents, because cis/trans becomes ambiguous about which pair of groups to reference — E/Z uses CIP priorities to resolve this unambiguously
CIt breaks down only when one substituent has a heteroatom (O, N, or halogen), which reverses the E/Z designation
DIt never breaks down — Z and cis always describe identical compounds
Question 3 True / False

In IUPAC nomenclature of alkenes, the double bond position must be given the lowest possible locant when numbering the parent chain.

TTrue
FFalse
Question 4 True / False

For any alkene, Z typically corresponds to the cis isomer and E generally corresponds to the trans isomer.

TTrue
FFalse
Question 5 Short Answer

Why is the E/Z system necessary for trisubstituted or tetrasubstituted alkenes, and what would go wrong if we relied on cis/trans labels instead?

Think about your answer, then reveal below.