Questions: Jacobi Fields

3 questions to test your understanding

Score: 0 / 3
Question 1 Multiple Choice

On a sphere of radius 1 (constant curvature K = 1), the Jacobi equation along a geodesic becomes J'' + J = 0. The solutions are J(t) = A sin(t) + B cos(t). This means Jacobi fields vanish (have conjugate points) at t = π. What does this imply geometrically?

AGeodesics on the sphere are undefined past t = π
BAll geodesics from a point refocus at the antipodal point (distance π), and geodesics beyond that distance are no longer minimizing
CThe curvature changes sign at t = π
DThe exponential map becomes complex-valued at t = π
Question 2 True / False

In a Riemannian manifold with non-positive sectional curvature (K ≤ 0), there are no conjugate points along any geodesic.

TTrue
FFalse
Question 3 Short Answer

Why are Jacobi fields important for understanding the second variation of arc length?

Think about your answer, then reveal below.