Questions: KAM Theorem

4 questions to test your understanding

Score: 0 / 4
Question 1 Multiple Choice

A two-degree-of-freedom Hamiltonian system is integrable, with orbits on 2-tori characterized by two frequencies ω₁ and ω₂. When a small perturbation is added, which tori survive?

AAll tori survive — Hamiltonian systems are structurally stable
BNo tori survive — any perturbation destroys all regular structure
CTori whose frequency ratio ω₁/ω₂ is sufficiently irrational (satisfying a Diophantine condition) survive with slight deformation. Tori with rational or near-rational frequency ratios are destroyed.
DOnly tori with rational frequency ratios survive, because resonant orbits are the most stable
Question 2 Multiple Choice

In a system with two degrees of freedom, KAM tori are two-dimensional surfaces in four-dimensional phase space (restricted to a three-dimensional energy surface). Why do these tori confine chaotic orbits?

AThey don't confine orbits — chaotic orbits can cross KAM tori freely
BA 2D torus in a 3D energy surface divides the surface into an inside and an outside — a chaotic orbit on one side cannot cross to the other, because that would require passing through the torus, which is invariant
CKAM tori act as energy barriers, reflecting chaotic orbits
DThey confine orbits only in integrable systems, not in perturbed systems
Question 3 True / False

The KAM theorem guarantees that the solar system is stable for all time.

TTrue
FFalse
Question 4 Short Answer

Explain why the golden ratio is considered the 'most irrational' number and why this matters for KAM theory.

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