Questions: Downward Löwenheim-Skolem Theorem

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

ZFC set theory proves that uncountable sets exist. By the Downward Löwenheim-Skolem theorem, ZFC has a countable model. A student says this is a contradiction: 'a countable model cannot contain uncountable sets.' What is the correct resolution?

AZFC cannot actually prove uncountable sets exist within a countable model
BThe countable model contains a set that appears uncountable from inside the model because no bijection to ω exists within the model itself
CThe theorem only applies if ZFC is consistent, and ZFC might be inconsistent
DThe model is only 'countable' in an informal sense; technically it contains uncountably many elements
Question 2 Multiple Choice

A logician wants to write a countable set of first-order axioms whose models are all and only uncountable structures. Can this be done?

AYes — just add the axiom 'there exist uncountably many elements' in first-order syntax
BYes — Cantor's diagonal argument can be transcribed into a finite set of first-order axioms
CNo — the Downward Löwenheim-Skolem theorem guarantees any such theory with an infinite model also has a countable model
DNo — but only because first-order logic has no quantifiers that range over sets
Question 3 True / False

The Downward Löwenheim-Skolem theorem states that nearly every first-order theory has a countable model.

TTrue
FFalse
Question 4 True / False

The proof of Downward Löwenheim-Skolem constructs a countable elementary substructure by closing a countable seed set under Skolem functions — and the closure of a countable set under countably many functions is countable.

TTrue
FFalse
Question 5 Short Answer

What does Skolem's paradox reveal about the nature of 'uncountability,' and how is the apparent contradiction resolved?

Think about your answer, then reveal below.