Questions: Magnetism: Paramagnetism and Diamagnetism
4 questions to test your understanding
Score: 0 / 4
Question 1 Multiple Choice
Pauli paramagnetism in metals is temperature-independent, while Curie paramagnetism in insulators follows χ ∝ 1/T. What causes this fundamental difference?
AMetals have stronger magnetic moments than insulators
BIn metals, the Pauli exclusion principle restricts spin flips to the ~k_BT energy shell near E_F; the number of available spins grows as T but each contributes less by 1/T, and these effects cancel. In insulators, all localized moments are free to reorient, so thermal disorder (∝ T) directly competes with field alignment (∝ 1/T)
CThe crystal structure of metals suppresses the temperature dependence
DInsulators have more unpaired electrons per atom
In Curie paramagnetism, N independent moments each contribute μ²B/3k_BT to the susceptibility, giving χ = Nμ²/(3k_BT) — pure competition between magnetic energy and thermal energy. In Pauli paramagnetism, the Fermi sea blocks most spin flips. Only electrons within ~k_BT of E_F can respond, but the density of these electrons (proportional to g(E_F)) is temperature-independent at leading order. The result is χ_Pauli = μ_B² g(E_F), independent of T. The ratio χ_Pauli/χ_Curie ~ k_BT/E_F ~ 1/100 at room temperature — Pauli paramagnetism is much weaker.
Question 2 Multiple Choice
Lenz's law applied at the atomic level explains diamagnetism: an applied field induces orbital currents that oppose the field. Why is diamagnetic susceptibility typically so small?
ADiamagnetism is small because the induced currents are on the atomic scale — the induced moment per atom is proportional to <r²>, the mean square orbital radius, which is tiny (~Ų), and the proportionality constant involves e²/mc², which is very small
BDiamagnetism is only present in superconductors
CThe diamagnetic response cancels with the paramagnetic response in most materials
DOnly core electrons contribute to diamagnetism
The Langevin diamagnetic susceptibility per atom is χ_dia = -e²N<r²>/(6mc²), where <r²> is the mean square distance of electrons from the nucleus. With <r²> ~ 1 Ų and N ~ 10-30 electrons, the susceptibility is of order -10^{-5} to -10^{-6} in CGS units. This is universally present but easily overwhelmed by paramagnetism when unpaired spins exist. Materials with no unpaired electrons (noble gases, many ionic crystals, bismuth) show measurable diamagnetism.
Question 3 True / False
Superconductors are 'perfect diamagnets' with χ = -1. This is qualitatively different from ordinary diamagnetism.
TTrue
FFalse
Answer: True
Ordinary (Langevin/Larmor) diamagnetism gives tiny susceptibilities (χ ~ -10^{-5}) from atomic-scale induced currents. Superconducting diamagnetism (the Meissner effect) gives χ = -1 (perfect screening) from macroscopic persistent currents that flow on the surface and completely expel the magnetic field from the interior. The physical mechanisms are completely different: Larmor diamagnetism is a perturbative response of individual atoms, while the Meissner effect is a collective quantum phenomenon involving the macroscopic coherence of the superconducting condensate.
Question 4 Short Answer
Why do rare earth ions often have much larger paramagnetic moments than transition metal ions, despite both having unpaired f or d electrons?
Think about your answer, then reveal below.
Model answer: In rare earth ions, the 4f electrons are deep inside the atom, well-shielded from the crystal electric field by the outer 5s and 5p shells. Spin-orbit coupling is strong and acts on the full J = L + S multiplet, and the crystal field is too weak to quench the orbital angular momentum. The moment is μ = g_J√(J(J+1)) μ_B with the full J value. In transition metal ions, the 3d electrons are the outermost shell and experience strong crystal fields that typically quench the orbital angular momentum (L is frozen). The moment is approximately μ ≈ 2√(S(S+1)) μ_B with g ≈ 2 and only the spin contribution. Since J (with both L and S) can be much larger than S alone, rare earth moments are often larger.
This is the origin of Hund's rules applied to solids: rare earths follow the free-ion J values closely, while transition metals are often 'spin-only' due to crystal field quenching of L.