Explain why boron chemistry is dominated by electron-deficient compounds and cluster structures, while aluminum — in the same group — forms conventional ionic and covalent compounds.
Think about your answer, then reveal below.
Model answer: Boron has three valence electrons but four valence orbitals (2s + three 2p), making it inherently electron-deficient — it cannot form enough conventional two-center, two-electron bonds to fill its octet. This forces boron into unconventional bonding: three-center two-electron bonds (as in diborane B₂H₆), electron-deficient bridge bonds, and polyhedral cluster compounds (boranes, carboranes). Aluminum, though also in Group 13 with three valence electrons, is much larger and more electropositive. It readily forms Al³⁺ in ionic compounds or uses its size to achieve higher coordination numbers (6 in Al₂O₃) through conventional bonding. Al can also form electron-deficient bridges (Al₂Cl₆ is a dimer with bridging chlorides), but this tendency is less dominant than in boron because aluminum's larger size and lower ionization energy favor ionic character.
This contrast between boron and aluminum is one of the clearest examples of the first-row anomaly combined with size effects. Boron's small size forces it into exotic bonding arrangements that are characteristic of its chemistry but unusual for the rest of the group.