Questions: Markovnikov's Rule and Regioselectivity in Addition Reactions

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

HBr adds to 2-methylpropene [(CH₃)₂C=CH₂]. Which product forms predominantly, and why?

ABr on the terminal carbon (CH₂), because HBr adds so that H goes to the less substituted carbon
BBr on the central carbon [(CH₃)₂CBr–CH₃], because the secondary carbocation intermediate is more stable than the primary
CBr on the central carbon, because the central carbon has fewer hydrogens and Markovnikov's rule is a fixed law
DAn equal mixture of both products, because carbocation stability cannot predict regiochemistry
Question 2 Multiple Choice

HBr is added to propene (CH₃–CH=CH₂) in the presence of peroxides. Where does the bromine end up?

AOn C-2 (the more substituted carbon), following Markovnikov's rule
BOn C-1 (the terminal carbon), anti-Markovnikov, because the reaction proceeds through a radical intermediate
COn C-1 (the terminal carbon), because peroxides reverse carbocation stability
DOn C-2, because peroxides do not affect the regiochemistry of electrophilic addition
Question 3 True / False

Markovnikov's rule predicts that in HBr addition to propene, bromine adds to C-2 (the more substituted carbon) because this pathway proceeds through a more stable secondary carbocation intermediate.

TTrue
FFalse
Question 4 True / False

Anti-Markovnikov additions violate Markovnikov's rule because they place hydrogen on the more substituted carbon rather than the less substituted one.

TTrue
FFalse
Question 5 Short Answer

Hydroboration-oxidation and radical HBr addition both give anti-Markovnikov products. What mechanistic feature do they share that explains this, and how does it differ from standard electrophilic HBr addition?

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