Questions: Mechanical Energy Balance with Pump and Turbine Work
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
A pump moves water from a lower tank to an elevated tank through a long pipe. After applying the mechanical energy equation, a student finds H_pump = 40 m but the elevation difference is only 30 m and velocity/pressure differences are negligible. What happened to the missing 10 m of head?
AIt was stored as potential energy in the pipe walls
BIt was dissipated as heat by viscous friction in the pipe (head loss)
CIt was converted to turbine work downstream
DThe pump under-performed; 10 m of head was never delivered to the fluid
The energy equation is a strict accounting statement: H_pump = Δz + H_turbine + H_loss. With no turbine and 30 m of elevation gain, the remaining 10 m must equal H_loss — energy permanently destroyed by viscous friction and converted to heat. Head loss always appears on the outlet side of the equation and can never be recovered.
Question 2 Multiple Choice
A pump delivers Q = 0.05 m³/s against a pump head of H = 30 m. The pump's efficiency is η = 0.75. What shaft power must be supplied to the pump?
AρgQH = 14.7 kW — shaft power equals hydraulic power
BρgQH / η = 19.6 kW — shaft power is higher because energy is lost in the pump itself
Cη × ρgQH = 11.0 kW — shaft power is lower because the pump multiplies input power
Dρg Q H η² = 8.3 kW — two efficiency factors apply, one for suction and one for discharge
The hydraulic power delivered to the fluid is P_hydraulic = ρgQH ≈ 14.7 kW. But because the pump is only 75% efficient, not all shaft power becomes fluid power — some is lost to friction, heat, and mechanical losses inside the pump. Therefore P_shaft = ρgQH / η = 14.7 / 0.75 ≈ 19.6 kW. Option A is the common error of forgetting that shaft power must be greater than delivered hydraulic power when efficiency < 1.
Question 3 True / False
In the mechanical energy equation, head loss appears on the outlet side of the equation because it represents energy removed from the fluid, just like turbine head.
TTrue
FFalse
Answer: False
Head loss and turbine head are both on the outlet (right) side, but for fundamentally different reasons. Turbine head represents useful work extracted — energy transferred to rotating machinery that can do work elsewhere. Head loss represents energy permanently destroyed by viscous friction and converted to heat; it cannot be recovered or redirected. The two terms have opposite physical significance: one is useful extraction, the other is irreversible waste.
Question 4 True / False
The concept of 'head' expresses each energy term in the mechanical energy equation as an equivalent height in meters, obtained by dividing energy per unit weight (J/N) by the gravitational constant.
TTrue
FFalse
Answer: True
Dividing each energy term (J/kg) by g gives units of meters — a 'height equivalent' of energy. Pressure head P/ρg is the height a static column would reach; velocity head V²/2g is the kinetic energy expressed as height; elevation head z is the actual height. Expressing everything in meters of head makes all terms directly comparable and greatly simplifies piping system calculations.
Question 5 Short Answer
A hydroelectric turbine extracts H_turbine = 50 m of head from water flowing at Q = 2 m³/s, and the turbine's efficiency is 0.85. What is the shaft power output, and why is it less than ρgQH_turbine?
Think about your answer, then reveal below.
Model answer: P_shaft = η × ρgQH_turbine = 0.85 × 1000 × 9.81 × 2 × 50 ≈ 835 kW. It is less than the full hydraulic power (ρgQH_turbine ≈ 981 kW) because the turbine cannot convert all fluid energy to shaft work — internal friction, fluid leakage, and mechanical losses dissipate some energy within the turbine itself.
The hydraulic power available from the fluid equals ρgQH_turbine. A turbine with efficiency η < 1 converts only a fraction of that to useful shaft output; the rest is dissipated internally. This mirrors the pump case: shaft input > hydraulic output for pumps (η < 1 means you pay more than you get), and shaft output < hydraulic input for turbines (η < 1 means you get less than is available).