Questions: Memoization and Tabulation

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

You need to solve a DP problem where the full subproblem space has 10,000 entries, but computing the final answer only requires visiting about 200 of them. Which implementation strategy has a clear practical advantage here?

ATabulation — iterating in a fixed order is always faster than recursion
BMemoization — it computes only the subproblems actually needed, avoiding the other 9,800
CBoth are equivalent; tabulation skips unneeded subproblems automatically
DNeither; the optimal approach is to reformulate the recurrence to eliminate unused subproblems
Question 2 Multiple Choice

You have a correct recursive solution for longest common subsequence using memoization. You now want to reduce space from O(mn) to O(n). Which approach makes this optimization straightforward, and why?

AMemoization — you can evict cache entries once they are no longer reachable
BTabulation — because you control the iteration order, you can see that each row depends only on the previous row and discard completed rows
CBoth approaches; space optimization is symmetric between them
DNeither; reducing LCS space below O(mn) requires a completely different algorithm
Question 3 True / False

Memoizing a recursive function that has a bug in its base case will produce correct results once the base case is reached for the first time and cached.

TTrue
FFalse
Question 4 True / False

Tabulation can often use less memory than memoization for problems where every subproblem is needed, because tabulation avoids call stack overhead.

TTrue
FFalse
Question 5 Short Answer

Why does tabulation enable space optimizations (like reducing a 2D DP table to two 1D arrays) that are difficult to apply to memoization?

Think about your answer, then reveal below.