Questions: Mesh Current Method (Mesh Analysis)

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A circuit has two clockwise mesh currents I₁ and I₂ sharing a resistor R. What is the actual current flowing through R from the perspective of mesh 1?

AI₁ + I₂, because both mesh currents pass through the shared resistor
BI₁ − I₂, because the two mesh currents flow in opposite directions through the shared branch
CI₁ alone, because I₂ is a fictitious variable that doesn't affect the branch
DThe average (I₁ + I₂)/2, since the resistor is shared equally
Question 2 Multiple Choice

A 3 A current source lies on the boundary between mesh 1 and mesh 2. How should mesh analysis handle this?

AAssign the voltage across the current source as an unknown and include it in the KVL equation for each mesh
BIgnore the current source — ideal current sources have zero resistance and don't appear in KVL
CWrite KVL around the outer perimeter of both meshes combined (skipping the current source branch), then add the constraint I₁ − I₂ = 3 A
DSet I₁ = 3 A and I₂ = 0, since the source fixes the current in one mesh
Question 3 True / False

Mesh currents are fictitious variables — they are not directly measured anywhere in the physical circuit.

TTrue
FFalse
Question 4 True / False

Mesh analysis can be applied to any circuit, including those whose wires is expected to cross when drawn on a flat surface.

TTrue
FFalse
Question 5 Short Answer

Explain why a current source between two meshes prevents writing a standard KVL equation around either mesh, and describe how the supermesh technique resolves this problem.

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