Questions: Mirror Image Formation and Ray Diagrams
5 questions to test your understanding
Score: 0 / 5
Question 1 Multiple Choice
An object is placed 5 cm in front of a concave mirror with focal length 10 cm (inside the focal point). What type of image forms?
AA real, inverted image on the same side as the object
BA virtual, upright, magnified image located behind the mirror
CNo image forms, because objects inside the focal length produce no reflection
DA real, upright image located behind the mirror
When an object is inside the focal length of a concave mirror (d_o < f), the reflected rays diverge and must be extended backward to find their apparent source. This yields a virtual image (d_i < 0) behind the mirror that is upright and magnified. This is exactly how a makeup mirror works — you sit inside the focal length to get a magnified, upright view. The common misconception is that concave mirrors always form real images; they only do so when the object is beyond the focal point.
Question 2 Multiple Choice
A convex mirror has a focal length of −20 cm. An object is placed 30 cm in front of it. What can be said with certainty about the image?
AThe image is real, inverted, and located in front of the mirror
BThe image is real, upright, and located behind the mirror
CThe image is virtual, upright, and located behind the mirror
DThe image location depends on where exactly the object is placed relative to the focal point
Convex mirrors have a negative focal length, which means their focal point is behind the mirror (virtual focus). Applying the mirror equation: 1/d_i = 1/f − 1/d_o = 1/(−20) − 1/30 = −5/60, so d_i = −12 cm. The negative value confirms the image is behind the mirror — virtual. Magnification m = −d_i/d_o = 12/30 > 0, so the image is upright and diminished. Convex mirrors ALWAYS produce virtual, upright, diminished images regardless of object position, which is why they are used for wide-angle surveillance.
Question 3 True / False
A convex mirror always produces a virtual, upright, diminished image regardless of where the object is placed.
TTrue
FFalse
Answer: True
This is true. Because a convex mirror has a negative focal length, the mirror equation always yields a negative d_i (image behind the mirror) and a positive magnification less than 1 for any positive object distance. The focal point is virtual (behind the mirror), so parallel rays never converge in front of it — no real image can form. This is the key difference from concave mirrors, which can produce either real or virtual images depending on object position.
Question 4 True / False
A negative magnification value (m < 0) from the mirror equation indicates that the image is smaller than the object.
TTrue
FFalse
Answer: False
The sign of magnification encodes orientation, not size. A negative magnification means the image is inverted (upside down) relative to the object. The absolute value |m| determines size: |m| > 1 means the image is enlarged, |m| < 1 means diminished, |m| = 1 means same size. For example, a concave mirror forming a real image far beyond the center of curvature gives m = −3, meaning the image is inverted AND three times larger than the object.
Question 5 Short Answer
Why does placing an object inside the focal length of a concave mirror produce a virtual image rather than a real image? What does this mean physically?
Think about your answer, then reveal below.
Model answer: When the object is inside the focal length, the reflected rays diverge after reflection — they never actually converge in front of the mirror. Instead, an observer sees rays appearing to come from a point behind the mirror. This apparent source is the virtual image: light does not actually pass through it, and it cannot be projected onto a screen. Mathematically, d_o < f makes 1/d_i negative (d_i < 0), confirming the image is behind the reflecting surface.
The key physical point is that 'image location' always means where rays converge or appear to diverge from. A real image occurs when reflected rays actually cross in space in front of the mirror — you could catch it on a screen. A virtual image occurs when reflected rays diverge; the eye traces them backward to an apparent source that has no actual light. The focal point is the dividing line: objects beyond f produce converging reflected rays (real image); objects inside f produce diverging reflected rays (virtual image).