Questions: Mixed Strategy Equilibrium and Equilibrium in Randomized Strategies

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

In Matching Pennies, Player 2 mixes 50-50 between Heads and Tails. Why does Player 1 also play 50-50 in equilibrium?

APlayer 1 randomizes to prevent Player 2 from predicting their action and exploiting it
BPlayer 1 randomizes because Player 2's 50-50 mix makes Player 1 exactly indifferent between Heads and Tails
CPlayer 1 randomizes to maximize expected payoff by averaging over all possible outcomes
DPlayer 1 randomizes because no pure strategy is a best response to any strategy Player 2 could play
Question 2 Multiple Choice

An inspector and a firm play an inspection game. In equilibrium, the inspector audits with probability p* and the firm evades with probability q*. If the penalty for detected evasion doubles, what happens to the equilibrium audit probability p*?

Ap* increases — a higher penalty requires more audits to maintain deterrence
Bp* decreases — a higher penalty means fewer audits are needed to keep the firm indifferent between evading and complying
Cp* is unchanged — the firm's behavior is what adjusts, not the inspector's mixing
Dp* increases — the inspector's payoff from catching evasion is higher, so they audit more
Question 3 True / False

In a mixed-strategy Nash equilibrium, a player who randomizes between two pure strategies earns a higher expected payoff than if they had played either pure strategy alone.

TTrue
FFalse
Question 4 True / False

Nash's existence theorem guarantees that every finite strategic-form game has at least one Nash equilibrium, which may be in pure or mixed strategies.

TTrue
FFalse
Question 5 Short Answer

In a mixed-strategy equilibrium, a player's mixing probabilities are determined by the opponent's payoffs, not their own. Explain why.

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