Questions: NMDA Receptors: Structure and Properties

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A presynaptic neuron fires weakly, releasing a small amount of glutamate onto a postsynaptic cell that is near its resting membrane potential (around −65 mV). What happens to NMDA receptor current at that synapse?

ANMDA receptors open fully because glutamate is the only requirement for gating
BNMDA receptors open partially, passing a small calcium current proportional to the amount of glutamate
CNMDA receptors remain blocked by Mg²⁺ and pass little or no current, even though glutamate is bound
DNMDA receptors open but pass only sodium, not calcium, at resting potential
Question 2 Multiple Choice

Why does NMDA receptor opening require postsynaptic depolarization in addition to glutamate binding?

AGlutamate binds to both GluN1 and GluN2 subunits, and GluN2 only changes conformation when the membrane is depolarized
BA Mg²⁺ ion physically blocks the open pore at resting membrane potential; depolarization electrostatically expels it, allowing ion flow
CDepolarization causes conformational changes in the channel that increase its affinity for glutamate
DNMDA receptors require voltage-gated calcium channels to open first, which then depolarize the membrane to activate the NMDAR
Question 3 True / False

NMDA receptor opening requires simultaneous glutamate binding and postsynaptic membrane depolarization, making the receptor sensitive to the correlation between pre- and postsynaptic activity.

TTrue
FFalse
Question 4 True / False

NMDA receptors open faster than AMPA receptors and produce larger, more rapid excitatory currents in response to glutamate.

TTrue
FFalse
Question 5 Short Answer

Explain why the Mg²⁺ block makes NMDA receptors act as coincidence detectors, and why this property matters for learning.

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