Questions: Osmolarity Regulation and Collecting Duct Function

5 questions to test your understanding

Score: 0 / 5
Question 1 Multiple Choice

A patient has a mutation that prevents vasopressin from binding to its V2 receptor in the collecting duct. Despite normal vasopressin secretion, what would you expect this patient's urine to look like?

AHighly concentrated urine, because the medullary osmotic gradient forces water reabsorption regardless of vasopressin
BNormal urine concentration, because other hormones compensate for the vasopressin receptor defect
CLarge volumes of very dilute urine, because aquaporin-2 channels cannot be inserted into the collecting duct membrane without vasopressin signaling
DAlternating concentrated and dilute urine as the patient's plasma osmolarity fluctuates
Question 2 Multiple Choice

What is the direct cellular mechanism by which vasopressin increases water reabsorption in the collecting duct?

AVasopressin activates Na⁺/K⁺-ATPase pumps that indirectly pull water into the interstitium
BVasopressin binds to V2 receptors, triggering a cAMP cascade that causes aquaporin-2 vesicles to fuse with the apical membrane of principal cells
CVasopressin opens pre-existing aquaporin channels that are normally gated closed by phosphorylation
DVasopressin increases the osmolarity of the medullary interstitium, creating a stronger osmotic gradient to pull water out
Question 3 True / False

The medullary osmotic gradient that drives water reabsorption in the collecting duct is always present in the kidney, but water only moves out of the collecting duct when vasopressin is elevated.

TTrue
FFalse
Question 4 True / False

When plasma osmolarity falls below the normal setpoint (e.g., after drinking excess water), vasopressin secretion increases to compensate by retaining more water in the collecting duct.

TTrue
FFalse
Question 5 Short Answer

A person drinks 2 liters of water rapidly. Describe the sequence of hormonal and renal events that restore plasma osmolarity to normal within the following hour.

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