Explain why hydrogen has an oxidation state of +1 in water (H₂O) but −1 in sodium hydride (NaH), and what principle underlies this difference.
Think about your answer, then reveal below.
Model answer: In H₂O, oxygen is more electronegative than hydrogen, so oxygen 'wins' the shared electrons in the O–H bond. Hydrogen is assigned +1 because it is the electron-donor in the bond. In NaH, sodium is more electropositive (less electronegative) than hydrogen, so hydrogen 'wins' the shared electrons in the Na–H bond. Hydrogen is now the electron-acceptor, giving it an oxidation state of −1. The underlying principle is electronegativity: in the oxidation number system, the more electronegative atom in a bond is assigned all the shared electrons. When hydrogen bonds to an element more electropositive than itself (metals), hydrogen becomes the winner and takes on a negative oxidation state.
The peroxide and metal hydride exceptions both stem from the same principle: the standard rules (O = −2, H = +1) hold only when the usual electronegativity ordering applies. When oxygen bonds to oxygen, or hydrogen bonds to a metal more electropositive than itself, the usual hierarchy breaks down and the exceptions apply. Understanding the electronegativity basis means you can always derive the correct assignment rather than memorizing a list of exceptions.